• Title/Summary/Keyword: Diophantine Equation

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ON THE DIOPHANTINE EQUATION (5pn2 - 1)x + (p(p - 5)n2 + 1)y = (pn)z

  • Kizildere, Elif;Soydan, Gokhan
    • Honam Mathematical Journal
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    • v.42 no.1
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    • pp.139-150
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    • 2020
  • Let p be a prime number with p > 3, p ≡ 3 (mod 4) and let n be a positive integer. In this paper, we prove that the Diophantine equation (5pn2 - 1)x + (p(p - 5)n2 + 1)y = (pn)z has only the positive integer solution (x, y, z) = (1, 1, 2) where pn ≡ ±1 (mod 5). As an another result, we show that the Diophantine equation (35n2 - 1)x + (14n2 + 1)y = (7n)z has only the positive integer solution (x, y, z) = (1, 1, 2) where n ≡ ±3 (mod 5) or 5 | n. On the proofs, we use the properties of Jacobi symbol and Baker's method.

THE EXTENDIBILITY OF DIOPHANTINE PAIRS WITH FIBONACCI NUMBERS AND SOME CONDITIONS

  • Park, Jinseo
    • Journal of the Chungcheong Mathematical Society
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    • v.34 no.3
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    • pp.209-219
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    • 2021
  • A set {a1, a2, ⋯ , am} of positive integers is called a Diophantine m-tuple if aiaj + 1 is a perfect square for all 1 ≤ i < j ≤ m. Let Fn be the nth Fibonacci number which is defined by F0 = 0, F1 = 1 and Fn+2 = Fn+1 + Fn. In this paper, we find the extendibility of Diophantine pairs {F2k, b} with some conditions.

FIBONACCI AND LUCAS NUMBERS ASSOCIATED WITH BROCARD-RAMANUJAN EQUATION

  • Pongsriiam, Prapanpong
    • Communications of the Korean Mathematical Society
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    • v.32 no.3
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    • pp.511-522
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    • 2017
  • We explicitly solve the diophantine equations of the form $$A_{n_1}A_{n_2}{\cdots}A_{n_k}{\pm}1=B^2_m$$, where $(A_n)_{n{\geq}0}$ and $(B_m)_{m{\geq}0}$ are either the Fibonacci sequence or Lucas sequence. This extends the result of D. Marques [9] and L. Szalay [13] concerning a variant of Brocard-Ramanujan equation.

SOME CONDITIONS ON THE FORM OF THIRD ELEMENT FROM DIOPHANTINE PAIRS AND ITS APPLICATION

  • Lee, June Bok;Park, Jinseo
    • Journal of the Korean Mathematical Society
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    • v.55 no.2
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    • pp.425-445
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    • 2018
  • A set {$a_1,\;a_2,{\ldots},\;a_m$} of positive integers is called a Diophantine m-tuple if $a_ia_j+1$ is a perfect square for all $1{\leq}i$ < $j{\leq}m$. In this paper, we show that the form of third element in Diophantine pairs and develop some results which are needed to prove the extendibility of the Diophantine pair {a, b} with some conditions. By using this result, we prove the extendibility of Diophantine pairs {$F_{k-2}F_{k+1},\;F_{k-1}F_{k+2}$} and {$F_{k-2}F_{k-1},\;F_{k+1}F_{k+2}$}, where $F_n$ is the n-th Fibonacci number.

The Diophantine Equation ax6 + by3 + cz2 = 0 in Gaussian Integers

  • IZADI, FARZALI;KHOSHNAM, FOAD
    • Kyungpook Mathematical Journal
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    • v.55 no.3
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    • pp.587-595
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    • 2015
  • In this article, we will examine the Diophantine equation $ax^6+by^3+cz^2=0$, for arbitrary rational integers a, b, and c in Gaussian integers and find all the solutions of this equation for many different values of a, b, and c. Moreover, two equations of the type $x^6{\pm}iy^3+z^2=0$, and $x^6+y^3{\pm}wz^2=0$ are also discussed, where i is the imaginary unit and w is a third root of unity.

ON THE DIOPHANTINE EQUATION (an)x + (bn)y = (cn)z

  • MA, MI-MI;WU, JIAN-DONG
    • Bulletin of the Korean Mathematical Society
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    • v.52 no.4
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    • pp.1133-1138
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    • 2015
  • In 1956, $Je{\acute{s}}manowicz$ conjectured that, for any positive integer n and any primitive Pythagorean triple (a, b, c) with $a^2+b^2=c^2$, the equation $(an)^x+(bn)^y=(cn)^z$ has the unique solution (x, y, z) = (2, 2, 2). In this paper, under some conditions, we prove the conjecture for the primitive Pythagorean triples $(a,\;b,\;c)=(4k^2-1,\;4k,\;4k^2+1)$.

On the Tarry-Escott and Related Problems for 2 × 2 matrices over ℚ

  • Supawadee Prugsapitak;Walisa Intarapak;Vichian Laohakosol
    • Kyungpook Mathematical Journal
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    • v.63 no.3
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    • pp.345-353
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    • 2023
  • Reduced solutions of size 2 and degree n of the Tarry-Escott problem over M2(ℚ) are determined. As an application, the diophantine equation αAn + βBn = αCn + βDn, where α, β are rational numbers satisfying α + β ≠ 0 and n ∈ {1, 2}, is completely solved for A, B, C, D ∈ M2(ℚ).