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http://dx.doi.org/10.5657/FAS.2012.0353

Age and Growth of Barbel Steed Hemibarbus labeo in Goe-san Lake in Korea  

Lee, Wan-Ok (Inland Fisheries Research Institute, National Fisheries Research and Development Institute)
Zhang, Ming-Ming (Department of Marine Biology, Pukyong National University)
Oh, Chul-Woong (Department of Marine Biology, Pukyong National University)
Baek, Jae-Min (Inland Fisheries Research Institute, National Fisheries Research and Development Institute)
Song, Kyung-Jun (Korea Inter-University Institute of Ocean Sciences, Pukyong National University)
Publication Information
Fisheries and Aquatic Sciences / v.15, no.4, 2012 , pp. 353-359 More about this Journal
Abstract
Age and growth of Hemibarbus labeo caught from Goe-san Lake in South Korea from March to November, 2011, were studied. A total of 201 specimens was collected, ranging from 110 to 580 mm in total length (TL). Males and females made up 47.9% and 52.1% of the sample, respectively. Marginal increment analyses showed that vertebral increments, each composed of one opaque and one hyaline zone, were deposited annually. Opaque edges were prevalent from June to July. The relationship between TL and vertebral radius was linear, with equations of R = 0.008TL - 0.208 (male) and R = 0.009TL - 0.272 (female). Regression equations between TL and total weight (TW) were $TW=9{\times}10^{-6}TL^{2.987}$ (male), $TW=8{\times}10^{-6}TL^{3.014}$ (female), and $TW=9{\times}10^{-6}TL^{2.988}$ (combined sexes), according to the von Bertalanffy growth equation. Back-calculated TL was expressed using the von Bertalanffy equation as follows: $L_t=438.25(1-e^{-0.175(t+0.164)})$ for males, $L_t=483.36(1-e^{-0.147(t+0.115)})$ for females, and $L_t=464.86(1-e^{-0.162(t+0.176)})$ for the sexes combined. The growth performances were 4.526, 4.536, and 4.544, respectively.
Keywords
Age; Growth; Barbel steed; Hemibarbus labeo; Goe-san Lake;
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